人教版选修4第64面实验:在AgNO_3溶液中滴加NaCl溶液生成AgCl沉淀,继续在AgCl悬浊液中滴加1 mol/L的NaI溶液振荡,白色沉淀转化为黄色沉淀,即AgCl转化为AgI沉淀。多数教师的解释:沉淀转化是因为AgCl悬浊液中的c(Ag~+)和滴加NaI溶液的c(I~-)乘积大于AgI的K_((?)p),使AgI(s)≒Ag~++I~-平衡逆向移动的结果,或者简单的解释为难溶电解质可以转化为更难溶的电解质。笔者认为 People’s Education Edition Elective 4 64th experiment: In the AgNO_3 solution, NaCl solution was added dropwise to form AgCl precipitate, continue to AgCl suspension was added dropwise 1mol / L NaI solution oscillation, the white precipitate into a yellow precipitate, that AgCl conversion For AgI precipitation. Most teachers explain that the precipitation transformation is because the product of Ag (Ag ~ +) in AgCl suspension and the c (I ~ ≒ Ag ~ ++ I ~ - balance the results of the reverse movement, or a simple explanation for the insoluble electrolyte can be transformed into more difficult to dissolve the electrolyte. the author thinks