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1.用等温法测定25°及40℃时KCl-KHCO_3-H_2O三元体系的溶解度.体系中无化合物和固溶体形成. 2.用单变曲线法研究25°和40℃Na~+-K~+∥Cl~--HCO_3~--H_2O四元交互体系的溶解度.体系中亦无化合物形成.溶解度图中有四个对应于纯组份的结晶相区,其中对应于碳酸氢钠的结晶相区最大,氯化钠结晶相区最小.体系中单变曲线相交成两个固液同组成的无变点(三饱和点),其固相分别为氯化钠、氯化钾及碳酸氢钠和氯化钾、碳酸氢钾及碳酸氢钠.氯化钾和碳酸氢钠成稳定盐对.
1. The isothermal method was used to determine the solubility of KCl-KHCO_3-H_2O ternary system at 25 ° and 40 ° C.No compounds and solid solution were formed in the system.2 Using the single curve method to study the solubility of Na + -K ~ + ∥Cl ~ --HCO_3 ~ --H_2O four-dimensional interaction system solubility of the system nor the formation of compounds in the solubility diagram there are four corresponding pure components of the crystalline phase, which corresponds to the sodium bicarbonate crystalline phase The largest in the region, and the smallest in the crystalline phase of sodium chloride.The single curve in the system intersects into two invariant points (three saturation points) with the same composition of solid and liquid, the solid phases are sodium chloride, potassium chloride and sodium bicarbonate Potassium chloride, potassium bicarbonate and sodium bicarbonate Potassium chloride and sodium bicarbonate as stable salts.