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第(60)题答案: 设生产甲种零件X天,生产乙种零件Y天,则生产丙种零件为30-X-Y(天),列联立方程如下: 由①得:X=6/5Y 代入②:600Y=750(30-6/5Y-Y) 化简,得:2,250Y=22,500 ∴ Y=10天……乙种零件生产天数 X=6/5×10=12天……甲种零件生产天数 30-X-Y=30-12-10=8天……丙种零件生产天数配套产品6,000套(能获最大利润) 上列天数不能变动,因为某种零件若增加生产一天,则另一种零件必定相应减少生产一天,从而
Question No. (60) Answer: Let X be a type of production of part A, produce a type Y part of Y, then produce a part of type C of 30-XY (days), and list the simultaneous equations as follows: From 1 to get: X=6/5Y 2:600Y=750(30-6/5Y-Y) Simplify, get: 2,250Y=22,500 ∴ Y=10 days...B part production days X=6/5×10=12 days...... A kind of parts Production days 30-XY=30-12-10=8 days...Crystal parts production days Supporting products 6,000 sets (maximum profit) The above-listed days cannot be changed because one part increases the production day and the other part Must reduce the production day accordingly