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在一些数学问题中,恰当应用“倒数法”,可使问题化难为易. 1.求值域或最值例1 求函数y=x/x~2+2x+2~(1/2)的值域. 解(1)当x=0时,y=0;
In some mathematics problems, the appropriate application of “countdown method” can make the problem difficult. 1.Evaluation domain or the most value example 1 Find the function y=x/x~2+2x+2~(1/2) Range. Solution (1) When x=0, y=0;