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数学期末考试中有这样一道题:设x~(10)-3=f(x)(x-1)~2+ax+b①(a,b∈R),其中f(x)是关于x的多项式,求a,b的值.通常的解法为
There is such a question in the final semester of mathematics: Let x (10) -3 = f (x) (x-1) ~ 2 + ax + b ① (a, b∈R) Polynomial, find the value of a, b. The usual solution is