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如图1所示的电路中,理想变压器原、副线圈的匝数比n_1:n2_1-22:5,原线圈接u_1-2202~(1/2)sin 100πt(V)的交流电,电阻R_1=R_1=25Ω,D为理想二极管,则()A.电阻Rà两端的电压为50 V B.二极管的反向耐压值应大于502~(1/2)V C.原线圈的输入功率为200 W D.通过副线圈的电流为3 A对于这个题目的选项,不同的资料给出的答案略有不同,主要是第四个选项的解答过程争议较多,在一些资料中列出了四种解法,争议主要集中在两种解法:解法一通过分析可以得到通过电阻R_1的电流
The circuit shown in Figure 1, the ideal transformer primary and secondary coil turns ratio n_1: n2_1-22: 5, the original coil connected u_1-2202 ~ (1/2) sin 100πt (V) of the AC resistance R_1 = R_1 = 25Ω, D is the ideal diode, () A. The voltage across the resistor Rà is 50 V B. The reverse voltage of the diode should be greater than 502 ~ (1/2) V C. The input power of the primary coil is 200 W D. The current through the secondary coil is 3 A. The answers to this question vary slightly from one source to the other, mainly due to the more controversial process of answering the fourth option. Four sources are listed in some sources Solution, the controversy is mainly concentrated in two solutions: Solution A through the analysis can be obtained through the resistor R_1 current