一、基本的古典概型问题问题1:一次投掷两颗骰子,求出现的点数之和为奇数的概率解法1:记A=“出现点数之和为奇数”。若取每次试验所有可能的点数(i,j)(表示第一颗骰子出现i点,第二颗骰子出现j点)为基本事件,i,j=1,2…6,则基本事件的总数n=62=36,且每个基本事件的发生是等可能的,因而是古典概型问题。其中A包含的基本事件数k=3×3+3×3=18,故P(A)=18/36=1/2。 First, the basic problem of classical problems Question 1: throwing two dice at a time, and find the sum of the odds of the probability of odd solution 1: Remember A = “the sum of points and odd ”. If we take all the possible points (i, j) of each test (representing the first dice appear i points, the second dice appear j points) as the basic event, i, j = 1,2 ... 6, the basic event The total number of n = 62 = 36, and the occurrence of each basic event is so possible that it is a classical probabilistic problem. Where A contains the basic event number k = 3 × 3 + 3 × 3 = 18, so P (A) = 18/36 = 1/2.