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题目(2012年高考(山东理))在等差数列{an}中,a3+a4+a5=84,a9=73.(Ⅰ)求数列{an}的通项公式;(Ⅱ)对任意m∈N*,将数列{an}中落入区间(9m,92m)内的项的个数记为bm,求数列{bm}的前m项和Sm.
(Ai = 84, a9 = 73). (I) The general formula for the {an} column; (II) for any m ∈N *, the number of terms falling within the interval (9m, 92m) in the sequence {an} is denoted as bm, and the first m terms and Sm of the sequence {bm} are found.