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图1中直线AB为一定质量的理想气体等容过程的p—t图线.原点O处的压强为p=0,温度t=0℃.现先使该气体从状态A出发,经过一等温膨胀过程,体积变为原来体积的2倍,然后保持体积不变,缓慢加热气体,使之达到某一状态F.此时其压强等于状态B的压强,试用作图法在所给的p—t图上,画出F的位置.(1992年高考试题) 考生在解此题中暴露出许多问题.现就其主要问
The straight line AB in Fig. 1 is the p-t graph of the ideal gas isometric process of a certain mass. The pressure at the origin O is p = 0 and the temperature is t = 0 C. The gas is now started from state A, passing through an isothermal During the expansion process, the volume becomes 2 times the original volume, and then the volume is held constant, and the gas is heated slowly to reach a certain state F. At this time, the pressure is equal to the pressure of state B, and is used as a graph in the given p— On the t chart, draw the position of F. (High exam questions in 1992) Candidates exposed many questions in solving this question.